BMS100 Past Test Questions
Chapter 20, Fall 2010
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  1. Which statement is true?
    1. The effects of a dominant gene are always visible or apparent in all individuals who have that gene.
    2. The effects of a dominant gene are visible or apparent only in individuals who also have the recessive allele (recessive version of the gene).
    3. The effects of a dominant gene are usually greater in individuals who are homozygous for (have two copies of) that gene.
    4. All of the above.
    5. None of the above.

  2. In order for a person to be a carrier of a genetic disorder,
    1. the person must be heterozygous
    2. the disorder must be caused by a recessive gene (or, by the absence of the dominant gene)
    3. both of the above
    4. none of the above

  3. If an albino individual has children with a person who is neither albino nor carrier of albinism gene, what are the expected outcomes among their children?
    1. 100% albinos
    2. 100% normal skin color, 0% are carriers of the albinism gene
    3. 100% normal skin color, 50% are carriers of the albinism gene
    4. 100% normal skin color, 100% are carriers of the albinism gene

  4. If a man and a woman, both of whom are carriers of the cystic fibrosis gene, have children together, what is the probability that a child of theirs will have cystic fibrosis disease?
    1. 0%
    2. 25%
    3. 50%
    4. 75%
    5. 100%

  5. Two of the alleles (genes) involved cystic fibrosis are "+" (dominant) and "cf" (recessive). Which genotype(s) result in production of excessively thick mucus?
    1. +/+ and +/cf
    2. +/+ only
    3. +/cf and cf/cf
    4. cf/cf only

  6. If a person is tested and found not to have the cf gene, then
    1. that person could not have a child who is directly affected by cystic fibrosis disease, regardless of the genotype of the other parent
    2. that person could not have a child who is a carrier of the cystic fibrosis gene, regardless of the genotype of the other parent
    3. both of the above
    4. none of the above

  7. All normal human karyotypes (chromosome sets) include
    1. 22 pairs of autosomes
    2. at least one X chromosome
    3. at least one Y chromosome
    4. both A. and B.
    5. all of the above

  8. Meiosis in females produces
    1. one ovum (egg) with 22 autosomes and one X chromosome
    2. one ovum (egg) with 44 autosomes and two X chromosomes
    3. four ova (eggs), each with 22 autosomes and either one X chromosome or one Y chromosome
    4. four ova (eggs), each with 22 autosomes and one X chromosome
    5. four ova (eggs), each with 44 autosomes and two X chromosomes

  9. The X chromosome
    1. is larger than the Y chromosome
    2. contains genes that cause an embryo to develop into a female
    3. contains genes that are not related to sex determination (have no effect on the sex of the child)
    4. both A. and B.
    5. both A. and C.

  10. If a woman is a carrier of the "color blindness gene," then what percentage of her ova ("eggs") contain the "color blindness gene?"
    1. 0%
    2. 25%
    3. 50%
    4. 75%
    5. 100%

  11. In relation to color vision / color blindness, what is the most rare genotype?
    1. XCXC (homozygous dominant)
    2. XCXc (heterozygous)
    3. XcXc (homozygous recessive)
    4. XCY
    5. XcY

  12. If a woman is a carrier of the “color blindness” gene, and a man has normal color vision, what phenotype is not possible among their children?
    1. son with normal color vision
    2. color-blind son
    3. color-blind daughter
    4. daughter who is a carrier of the color-blindness gene
    5. daughter who is neither color blind nor a carrier of the color-blindness gene

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